Find the Jordan form of \( A = \begin{bmatrix} 2 & -1 & -1 & -1 & 0 & -1/2 & -1 \\ 2 & 4 & -1 & 3 & -1 & -1/2 & -1 \\ -6 & -4 & 5 & -5 & 1 & 1 & 3 \\ -4 & -3 & 3 & -3 & 2 & 2 & 3\\ -6 & -4 & 3 & -5 & 3 & 3/2 & 3 \\ 0 & 0 & 0 & 0 & 0 & 2 & 0 \\ 8 & 5 & -5 & 7 & -2 & -5/2 & -3 \end{bmatrix} \) as well as an invertible matrix \( P \) such that \( P^{-1}AP \) is the Jordan form of \( A\). You may use Maple to do your computations, but I want to see your work building up a basis of generalized eigenvectors (i.e. don't just use the "JordanForm" command).
Copy/Paste into Maple:
A := Matrix(7, 7, {(1, 1) = 2, (1, 2) = -1, (1, 3) = -1, (1, 4) = -1, (1, 5) = 0, (1, 6) = -1/2, (1, 7) = -1,
(2, 1) = 2, (2, 2) = 4, (2, 3) = -1, (2, 4) = 3, (2, 5) = -1, (2, 6) = -1/2, (2, 7) = -1,
(3, 1) = -6, (3, 2) = -4, (3, 3) = 5, (3, 4) = -5, (3, 5) = 1, (3, 6) = 1, (3, 7) = 3,
(4, 1) = -4, (4, 2) = -3, (4, 3) = 3, (4, 4) = -3, (4, 5) = 2, (4, 6) = 2, (4, 7) = 3,
(5, 1) = -6, (5, 2) = -4, (5, 3) = 3, (5, 4) = -5, (5, 5) = 3, (5, 6) = 3/2, (5, 7) = 3,
(6, 1) = 0, (6, 2) = 0, (6, 3) = 0, (6, 4) = 0, (6, 5) = 0, (6, 6) = 2, (6, 7) = 0,
(7, 1) = 8, (7, 2) = 5, (7, 3) = -5, (7, 4) = 7, (7, 5) = -2, (7, 6) = -5/2, (7, 7) = -3});